2x^2-9x/x^2-5x-36

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Solution for 2x^2-9x/x^2-5x-36 equation:


D( x )

x^2 = 0

x^2 = 0

x^2 = 0

1*x^2 = 0 // : 1

x^2 = 0

x = 0

x in (-oo:0) U (0:+oo)

2*x^2-(5*x)-((9*x)/(x^2))-36 = 0

2*x^2-5*x-9*x^-1-36 = 0

2*x^2-5*x^1-9*x^-1-36*x^0 = 0

(2*x^3-5*x^2-36*x^1-9*x^0)/(x^1) = 0 // * x^2

x^1*(2*x^3-5*x^2-36*x^1-9*x^0) = 0

x^1

2*x^3-5*x^2-36*x-9 = 0

{ 1, -1, 3, -3, 9, -9 }

1

x = 1

2*x^3-5*x^2-36*x-9 = -48

1

-1

x = -1

2*x^3-5*x^2-36*x-9 = 20

-1

3

x = 3

2*x^3-5*x^2-36*x-9 = -108

3

-3

x = -3

2*x^3-5*x^2-36*x-9 = 0

-3

x+3

2*x^2-11*x-3

2*x^3-5*x^2-36*x-9

x+3

-2*x^3-6*x^2

-11*x^2-36*x-9

11*x^2+33*x

-3*x-9

3*x+9

0

2*x^2-11*x-3 = 0

DELTA = (-11)^2-(-3*2*4)

DELTA = 145

DELTA > 0

x = (145^(1/2)+11)/(2*2) or x = (11-145^(1/2))/(2*2)

x = (145^(1/2)+11)/4 or x = (11-145^(1/2))/4

x in { (11-145^(1/2))/4, (145^(1/2)+11)/4, -3}

x in { (11-145^(1/2))/4, (145^(1/2)+11)/4, -3 }

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